Here's my guide to solve those simple, yet tricky quadratic equations.

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First you need to undertand the rules.

a? + 2ab + b? = (a+b)(a+b) = (a+b)?
a? + b? = (a+b)(a-b)
a? - 2ab + b? = (a-b)(a-b) = (a-b)?

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So a question like x? + 6x + 9 = 0
So the x? in that equation would be the "a?" and the 9 would be the "b?", so the "b" would be 3 and the "a" would be just x. To check you see that since the middle part is 2ab, it would be 2(x)(3) because 3 is b, and 2 times 3 is 6, so it would be 6x, and that's correct.
So now you would get (a+3)(a+3) = 0, or (a+3)? = 0, or a = -3 and that's your answer.

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A different variant is like this x? + 10x + 9 = 0 which does not follow the a? + 2ab + b? = 0 pattern.
You can see that 9 has the factors 1, 3, 9.
You can also see that 1 and 9 makes 10.
So you will get (x+1)(x+9) = 0, x = (-1, -9)

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Kidaime asked "Can someone please explain to me how i can do this in steps?
9y? - 6y + 1 = 0"

Well this is the equation a? - 2ab + b? because of the -6y, but they throw you off by putting a 9 there.
The 9y? is actually (3y)? so, the a in that equation would be 3y and the b would be 1.
Now the 2ab in that above equation is -6y, since the a is 3y and the b is 1, so 2(3y)(1), is 6y, And when you put it in to the answer you get
(3y - 1)(3y - 1) = 0 or (3y - 1)? = 0
y = 1/3

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And that's all for quadratic equations for now.
Quadratic equations is a tricky thing, and harder equations are beyond my limited knowledge, but if you have any trouble just leave a comment and I will try my best to help!

mhy are u posting these stuff? can i post my homework here, lol:D:D

Yes you can. I was just explaining to Benjamin how to do these equations, so might as well do an article to explain.